**Problem :-**Write A C++ Program To Find Sum Of Series 1+1/2^2+1/3^3+…..+1/n^n .

**Logic :-**This Below Solve this series in second ,use this statement and use it .you also can modify and see the difference

**Syntax :-**

Series=1/pow(i,i);

After that statement you need to add all the statement .

**Solution :-**
#include<iostream>

#include<math.h>

using namespace std;

int main()

{

//By-Ghanendra Yadav

double sum=0,a;

int n,i;

cout<<"1+1/2^2+1/3^3+…..+1/n^n";

cout<<"\nEnter The Value Of n :\n";

cin>>n;

for(i=1;i<=n;++i)

{

a=1/pow(i,i);

sum+=a;

}

cout<<"Sum = "<<sum<<endl<<endl;

return 0;

}

**Output:-**
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